{"id":507,"date":"2020-11-30T07:59:23","date_gmt":"2020-11-30T07:59:23","guid":{"rendered":"https:\/\/pickedshares.com\/?p=507"},"modified":"2021-05-08T11:21:52","modified_gmt":"2021-05-08T11:21:52","slug":"engineering-mechanics-1-exercise-3-calculate-the-resulting-tensile-force","status":"publish","type":"post","link":"https:\/\/pickedshares.com\/en\/engineering-mechanics-1-exercise-3-calculate-the-resulting-tensile-force\/","title":{"rendered":"Calculate the resulting tensile force"},"content":{"rendered":"\n<p>This exercise is about the following questions:<\/p>\n\n\n\n<ul class=\"wp-block-list\"><li>How to calculate a component of a force?<\/li><li>How to calculate a resulting force?<\/li><\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Task<\/h3>\n\n\n\n<p>Two ropes are attached to an eyelet. Calculate the resulting tensile force on the eyelet. Does it act perpendicular?<\/p>\n\n\n\ngiven: <br>\nF<sub>1<\/sub> = 8,2 kN <br>\nF<sub>2<\/sub> = 9,7 kN <br>\n\u03b1 = 50\u00b0 <br>\n\u03b2 = 60\u00b0\n\n\n\n<figure class=\"wp-block-image size-large is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/pickedshares.com\/wp-content\/uploads\/2020\/11\/Screenshot_20201104-180219_Sketch.jpg\" alt=\"Eye with tensile forces\" class=\"wp-image-397\" width=\"388\" height=\"366\" srcset=\"https:\/\/pickedshares.com\/wp-content\/uploads\/2020\/11\/Screenshot_20201104-180219_Sketch.jpg 775w, https:\/\/pickedshares.com\/wp-content\/uploads\/2020\/11\/Screenshot_20201104-180219_Sketch-300x283.jpg 300w, https:\/\/pickedshares.com\/wp-content\/uploads\/2020\/11\/Screenshot_20201104-180219_Sketch-768x724.jpg 768w\" sizes=\"auto, (max-width: 388px) 100vw, 388px\" \/><figcaption>Eye with tensile forces<\/figcaption><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\">Solution<\/h3>\n\n\n\n<p>The following video is in german language. <\/p>\n\n\n<figure class=\"wp-block-embed-youtube wp-block-embed is-type-video is-provider-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"lyte-wrapper\" title=\"Technische Mechanik 1, &Uuml;bung 3 - Zugkraft berechnen\" style=\"width:640px;max-width:100%;margin:5px auto;\"><div class=\"lyMe hidef\" id=\"WYL_rFtYGCjt1kg\" itemprop=\"video\" itemscope itemtype=\"https:\/\/schema.org\/VideoObject\"><div><meta itemprop=\"thumbnailUrl\" content=\"https:\/\/pickedshares.com\/wp-content\/plugins\/wp-youtube-lyte\/lyteCache.php?origThumbUrl=https%3A%2F%2Fi.ytimg.com%2Fvi%2FrFtYGCjt1kg%2Fmaxresdefault.jpg\" \/><meta itemprop=\"embedURL\" content=\"https:\/\/www.youtube.com\/embed\/rFtYGCjt1kg\" \/><meta itemprop=\"duration\" content=\"PT4M33S\" \/><meta itemprop=\"uploadDate\" content=\"2020-10-26T08:55:20Z\" \/><\/div><meta itemprop=\"accessibilityFeature\" content=\"captions\" \/><div id=\"lyte_rFtYGCjt1kg\" data-src=\"https:\/\/pickedshares.com\/wp-content\/plugins\/wp-youtube-lyte\/lyteCache.php?origThumbUrl=https%3A%2F%2Fi.ytimg.com%2Fvi%2FrFtYGCjt1kg%2Fmaxresdefault.jpg\" class=\"pL\"><div class=\"tC\"><div class=\"tT\" itemprop=\"name\">Technische Mechanik 1, \u00dcbung 3 - Zugkraft berechnen<\/div><\/div><div class=\"play\"><\/div><div class=\"ctrl\"><div class=\"Lctrl\"><\/div><div class=\"Rctrl\"><\/div><\/div><\/div><noscript><a href=\"https:\/\/youtu.be\/rFtYGCjt1kg\" rel=\"nofollow\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/pickedshares.com\/wp-content\/plugins\/wp-youtube-lyte\/lyteCache.php?origThumbUrl=https%3A%2F%2Fi.ytimg.com%2Fvi%2FrFtYGCjt1kg%2F0.jpg\" alt=\"Technische Mechanik 1, &Uuml;bung 3 - Zugkraft berechnen\" width=\"640\" height=\"340\" \/><br \/>Watch this video on YouTube<\/a><\/noscript><meta itemprop=\"description\" content=\"An einer \u00d6se sind zwei Seile befestigt. Wie gro\u00df ist die Zugkraft an der \u00d6se und wirkt diese in lotrechte Richtung? In dem Video wird die resultierende Kraft in vertikaler Richtung berechnet und anschlie\u00dfend gepr\u00fcft, ob die resultierende horizontale Komponente Null ist. Diese \u00dcbung findet man auch auf https:\/\/pickedshares.com\/technische-mechanik-1-uebung-3-zugkraft-berechnen\/\"><\/div><\/div><div class=\"lL\" style=\"max-width:100%;width:640px;margin:5px auto;\"><\/div><figcaption><\/figcaption><\/figure>\n\n\n<p>The x-components of the two forces result to<\/p>\n\n\n\n<script src=\"https:\/\/cdnjs.cloudflare.com\/ajax\/libs\/mathjax\/2.7.7\/MathJax.js?config=TeX-AMS_HTML\" async=\"async\">  \/\/ A comment that hinders wxWidgets from optimizing this tag too much.\n<\/script>\n\n<div style=\"overflow:auto;\">\n<p>\\[\\tag{1} \\sum F_x= F_1\\cos(\\alpha)+F_2\\cos(\\beta)\\]<\/p>\n<\/div>\n<p>\\[\\tag{2} \\sum F_x= 10.12 kN\\]<\/p>\n\n\n\n<p>Assuming the transverse direction of the x-axis as the y-axis, a perpendicularly force would have to have a transverse component of zero. This is checked by<\/p>\n\n\n\n<script src=\"https:\/\/cdnjs.cloudflare.com\/ajax\/libs\/mathjax\/2.7.7\/MathJax.js?config=TeX-AMS_HTML\" async=\"async\">  \/\/ A comment that hinders wxWidgets from optimizing this tag too much.\n<\/script>\n\n<div style=\"overflow:auto;\">\n<p>\\[\\tag{3} \\sum F_y= -F_1\\sin(\\alpha)+F_2\\sin(\\beta)\\]<\/p>\n<\/div>\n<p>\\[\\tag{4} \\sum F_y= 2.12 kN\\]<\/p>\n\n\n\n<p>The transverse force is not zero, so the tensile force on the eyelet does not act perpendicular.<\/p>\n\n\n\n<p>The resulting force F ist calculated from the x- and y-components as follows:<\/p>\n\n\n\n<script src=\"https:\/\/cdnjs.cloudflare.com\/ajax\/libs\/mathjax\/2.7.7\/MathJax.js?config=TeX-AMS_HTML\" async=\"async\">  \/\/ A comment that hinders wxWidgets from optimizing this tag too much.\n<\/script>\n<p>\\[\\tag{5} F= \\sqrt{F_x^2+F_y^2} \\]<\/p>\n<p>\\[\\tag{6} F = 10.34 kN\\]<\/p>\n\n\n\n<p>Do you already know the other <a href=\"https:\/\/pickedshares.com\/en\/tag\/resulting-force\/\">exercises about resulting forces<\/a>?<\/p>\n","protected":false},"excerpt":{"rendered":"<p> ... <a title=\"Calculate the resulting tensile force\" class=\"read-more\" href=\"https:\/\/pickedshares.com\/en\/engineering-mechanics-1-exercise-3-calculate-the-resulting-tensile-force\/\" aria-label=\"Read more about Calculate the resulting tensile force\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":396,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[21,60],"tags":[47,29],"class_list":["post-507","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-engineering-mechanics-i","category-exercises","tag-resultant-force","tag-statics","infinite-scroll-item","masonry-post","generate-columns","tablet-grid-50","mobile-grid-100","grid-parent","grid-33"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.4 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Calculate the resulting tensile force &#8226; pickedshares<\/title>\n<meta name=\"description\" content=\"Two forces act on an eyelet. 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